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rules of differentiation and integration pdf

Basic Differentiation Rules Basic Integration Formulas DERIVATIVES AND INTEGRALS © Houghton Mifflin Company, Inc. 1. Rules of Differentiation (Economics) Contents Toggle Main Menu 1 Differentiation 2 The Constant Rule 3 The Power Rule 4 The Sum or Difference Rule 5 The Chain Rule 6 The Exponential Function 7 Product Rule 8 Quotient Rule 9 Test Yourself 10 External Resources On completion of this tutorial you should be able to do the following. Differentiate the function $y=(1+2x^2)(3x+x^4)$. Example • Bring the existing power down and use it to multiply. The rate of change of sales of a brand new soup (in thousands per month) is given by R(t) = + 2, where t is the time in months that the new product has been on the market. Recall that the exponential function $f(x)= e^x$.

4. 28. Calculus is usually divided up into two parts, integration and differentiation. Differentiate the function $y=(x^2+3x+6)(x^3+5x^2+2x+1)$. They are $m'(x)=4x^3$ and $n'(x)=-9x^-4$ respectively. Note: This is intuitive as a constant function is a horizontal line which has a slope of zero.

22. You can get one-to-one support from Maths-Aid. Differentiate the function $f(x)=3x^{-3}$. The derivative of $y=4x^5+x^2-10x^{-2}+3$ is therefore: \begin{align} \dfrac{\mathrm{d} y}{\mathrm{d} x}&=20x^4+2x-\left(-20x^{-3}\right)-0\\ &=20x^4+2x+20x^{-3} \end{align}. Differentiate the function $y=2x^{~\frac{1}{4}~}$. To differentiate a sum (or difference) of terms, differentiate each term separately and add (or subtract) the derivatives. Differentiation Rules: To understand differentiation and integration formulas, we first need to understand the rules. Differentiate the function $g(x)=x^4-3x^{-3}$.

Riemann Sums: 11 nn ii ii ca c a 111 nnn ii i i iii ab a b 1 We have already found the derivatives of these two functions. 31. This rule is used to differentiate a function of another function, $y=f(g(x))$.To differentiate $y=f(g(x))$, let $u=g(x)$ so that we have $y$ as a function of $u$, $y=f(u)$. The derivative of this function is the same as the function itself: \[\dfrac{\mathrm{d} f}{\mathrm{d} x}= e^x\] If the power to which $e$ is raised is a function of $x$, $g(x)$ say, we have $f(x)= e^{g(x)}$ and: \[\dfrac{\mathrm{d} f}{\mathrm{d} x}=g'(x) e^{g(x)}\] where $g'(x)$ denotes the derivative of the function $g(x)$. The product rule says the derivative of $y$ is: \[\dfrac{\mathrm{d} y}{\mathrm{d} x}=u\dfrac{\mathrm{d} v}{\mathrm{d} x}+v\dfrac{\mathrm{d} u}{\mathrm{d} x}\], In words this says that “the derivative of a product of two functions is the derivative of the first, times the second, plus the first times the derivative of the second.”.

The first step is to set $u=g(x)$, where $g(x)=3x+x^4$, and differentiate $u$ with respect to $x$: \[\dfrac{\mathrm{d} u}{\mathrm{d} x}=3+4x^3\] The next step is to differentiate $y$ with respect to $u$.

Apply Newton’s rules of differentiation to basic functions. Differentiation of a simple power multiplied by a constant To differentiate s = atn where a is a constant. You proba-bly learnt the basic rules of differentiation and integration … b a f xdx Fb Fa, where F(x) is any antiderivative of f(x). The derivative a function of the form $y=a$ (where $a$ is a constant) is zero: \[\dfrac{\mathrm{d} y}{\mathrm{d} x}=0\].

Differentiation and Integration Rules A derivative computes the instantaneous rate of change of a function at different values.

The derivative of $u$ with respect to $x$ is: \[\dfrac{\mathrm{d} u}{\mathrm{d} x}=2x\] and the derivative of $v$ with respect to $x$ is: \[\dfrac{\mathrm{d} v}{\mathrm{d} x}=3x^2-2\] Using the quotient rule, we have: \begin{align} \dfrac{\mathrm{d} y}{\mathrm{d} x}&=\dfrac{v\dfrac{\mathrm{d} u}{\mathrm{d} x}-u\dfrac{\mathrm{d} v}{\mathrm{d} x}~}{v^2}\\ &=\dfrac{(x^3-2x+1)2x-(x^2+3)(3x^2-2)}{(x^3-2x+1)^2} \end{align} After multiplying out the brackets in the numerator and cancelling where possible, this simplifies to \[\frac{dy}{dx}={-x^4-11x^2+2x+6}{(x^3-2x+1)^2}\], Test yourself: Numbas test on differentiation, Test yourself: Numbas test on differentiation, including the chain, product and quotient rules. Differentiation is the method of evaluating a function's derivative at any time. As with differentiation, there are some basic rules we can apply when integrating functions. Some of the fundamental rules for differentiation are given below: Sum or Difference Rule: The derivative of $u$ with respect to $x$ is: \[\dfrac{\mathrm{d} u}{\mathrm{d} x}=4x\] and the derivative of $v$ with respect to $x$ is: \[\dfrac{\mathrm{d} v}{\mathrm{d} x}=3+4x^3\] Using the product rule, we have: \begin{align} \dfrac{\mathrm{d} y}{\mathrm{d} x}&=u\dfrac{\mathrm{d} v}{\mathrm{d} x}+v\dfrac{\mathrm{d} u}{\mathrm{d} x}\\ &=(1+2x^2)(3+4x^3)+(3x+x^4)4x \end{align} After multiplying out the brackets and cancelling where possible, this simplifies to: \[\dfrac{\mathrm{d} y}{\mathrm{d} x}=12x^5+4x^3+18x^2+3\]. Differentiation and integration are basic mathematical operations with a wide range of applications in many areas of science. 2. f x e x3 ln , 1,0 Example: Use implicit differentiation to find dy/dx given e x yxy 2210 Example: Find the second derivative of g x x e xln x Integration Rules for Exponential Functions – Let u … 19. ContentsToggle Main Menu 1 Differentiation 2 The Constant Rule 3 The Power Rule 4 The Sum or Difference Rule 5 The Chain Rule 6 The Exponential Function 7 Product Rule 8 Quotient Rule 9 Test Yourself 10 External Resources. Let $m(x)=x^4$ and $n(x)=3x^{-3}$. It is therefore important to have good methods to compute and manipulate derivatives and integrals. Fundamental Theorem of Calculus: x a d F xftdtfx dx where f t is a continuous function on [a, x]. Each is the reverse process of the other. Rewriting $y$ in terms of $u$ gives: \[y=u^2\] and so \[\dfrac{\mathrm{d} y}{\mathrm{d} u}=2u\] Next, using the chain rule, we have: \begin{align} \dfrac{\mathrm{d} y}{\mathrm{d} x}&=\dfrac{\mathrm{d} y}{\mathrm{d} u}\times \dfrac{\mathrm{d} u}{\mathrm{d} x}\\ &=2u\times (3+4x^3) \end{align} The final step is to substituting $u=3x+x^4$: \begin{align} \dfrac{\mathrm{d} y}{\mathrm{d} x}&=2u\times (3+4x^3)\\ &=2(3x+x^4)(3+4x^3) \end{align} After multiplying out the brackets and cancelling where possible, this simplifies to: \[2x(4x^6+15x^3+9)\]. Differentiate the function $f(h)= e^{h^2}$. Academic Skills Kit, Newcastle University, Newcastle upon TyneNE1 7RU, United Kingdom.Email Webmaster, Last updated 12 March, 2018

Differentiate the function $y=4x^5+x^2-10x^{-2}-3$.

(x) The chain rule says that when we take the derivative of one function composed with The quotient rule says the derivative of $y$ is: \[\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{v\dfrac{\mathrm{d} u}{\mathrm{d} x}-u\dfrac{\mathrm{d} v}{\mathrm{d} x}}{v^2}\] In words, this says that the derivative of a quotient is “the derivative of the numerator times the denominator, minus the numerator times the derivative of the denominator, all divided by the denominator squared”, Differentiate the function $y=\dfrac{x^2+3}{x^3-2x+1}$, Here $u=x^2+3$ and $v=x^3-2x+1$.

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